ajdelange
Active Member
The current that causes the heat loss is included in the current integral and the heat lost is included in the energy integral. You cannot separate them out just by measuring current. You would have to do a separate estimation of what portion of the energy measured by this method goes to heat by estimating the amount that goes to traction and subtracting that from the integral. Regen is also captured when total current is measured. Current draw becomes negative during regen and the integrals get smaller at such time as regeneration is taking effect.So far so good, I am not arguing to that. But so far the heat loss is not in this calculation. And the regen as well.
Seem? Is there any evidence that it is done otherwise? As I said I don't have any details but this is certainly the common sense approach and any data I am able to see in the car or get through the API supports it.I hate to argue with the scientific explanation you just did, but this doesn't seem to be the way the BMS calculates consumption shown under "used" for the trip.
Again, it is consistent with any observations I can get from the car or the API.And from the observations, this is not what the BMS is doing.
No, I don't think they do and I thus think they don't and thus I think the displayed energy use must include the I^2R losses just as it includes all the other losses.I think they don't want to do the hard work of calculation and messing it up, especially when 99% of their customer base will never drive above 75-80mph and experience massive heat loss.
Losses are appreciable at lower speed too. If you drive from point A to point B and back to point A the state of the car (once it cools down) is the same as when you departed. No energy was used in an ideal world. But in the real world you used quite a bit of energy and all of the energy you used is, thus, loss and not only loss but heat loss. You warmed the inverter transistors, you warmed the stator, you warmed the tires, you warmed the bearings, you warmed the gearbox, you warmed the air, you warmed the road bed, you warmed the water on road if it were present. How can the car separate out the I^2R losses? Why would anyone want it to? If it did somehow exclude I^2R losses I would lobby hard to get them included.
I think you must be misinterpreting what you are reading from the CAN bus because the notion that one type of loss is somehow separated out and deducted from all the others just doesn't make sense. It would be hard to do and we, as users, certainly wouldn't want it done.This is evident by the SOC readings from the CAN bus on a high-speed stretch, which doesn't match the kWh used in the trip meter, based on % of available capacity.
What, after all is SoC? It is the amount of charge in the battery relative to the battery's usable capacity. And what is the battery's usable capacity? The amount of charge it take to move it from one arbitrarily chosen state (empty - the state variable here is OC voltage) to another arbitrarily chosen state (full). This changes with time (the battery ages), temperature and load. It's a pretty simple matter to determine SoC if you know how many coulombs of charge are in the battery relative to the empty state, what the capacity is, and how many you have taken out or put in over a time period. As we have noted above it is pretty easy to accurately measure the total charge added or deducted but it is not at all simple to determine the capacity because our only observable is OC voltage and that doesn't change much with SoC. The Tesla's thus have very sophisticated algorithms that attempt to do this and they are probably the best in the world but even they cannot beat what we call "dilution of precision". Thus capacity estimates are all over the map for the same car over, say a month. Look at some of the plots people have posted to this thread.
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