camalaio
Active Member
24A cool to the touch of a #6 wire?
Yes. For reasons, it's 6/4 SOOW (not in wall) I believe. In a cool garage. The cable going into the car gets a bit warmer though, since it's thinner.
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24A cool to the touch of a #6 wire?
Yes you are really drawing less power. The dimmer switch analogy is not correct either, as a dimmer switch increases the resistance to a light bulb, that changes the total draw of the circuit according to Ohms Law, it does not dissipate the entire amount in heat, although they do often get warm.
Reducing your current by 50% means your line losses go down by 75%. That's the law
View attachment 509779
Dimmers switch off and on a triac, they don’t change the resistance of the light bulb. The bulb dims because it is on for only part of the sinewave and isn’t seeing the peaks of the AC voltage waveform.
The current is limited by the onboard charger (which is technically not an invertor because the battery requires DC, not AC) reduces the average battery charge voltage which reduces the battery charge current, which in turn reduces the AC input current to the selected value.Would be interesting to see how telsa limits the current through the onboard inverter.
... interesting... here's an online calculator.
Wire Gauge Size and Resistance Calculator - Inch Calculator
Voltage Drop Calculator - Inch Calculator
Have not taken EE class. Is this right?
#6 copper wire @ 5 ft
50A circuit
245V power
To charge 10 kW
@ 12A, voltage drop of 0.059v, so 0.71W loss
= 3.4 hours, so 2.41W loss on the wall.
= Add 200W loss per hour, so 682.31W loss
@ 16A, voltage drop of 0.0786v, so 1.26W loss
= 2.55 hour, so 3.21W loss
= Add 200W loss per hour, so 511.26W loss
@ 24A, voltage drop of 0.1179v, so 2.83W loss
= 1.7 hour, so 4.81W loss
= Add 200W loss per hour, so 342.83W loss
@ 32A, voltage drop of 0.1572v, so 5.03W loss
= 1.28 hour, so 6.44W loss
= Add 200W loss per hour, so 261.03W loss
Going from #6 wire to #4 wire, resistance drops from .0020 to .0012 ohm (so 40% less W loss on the wire)
... interesting... here's an online calculator.
Wire Gauge Size and Resistance Calculator - Inch Calculator
Voltage Drop Calculator - Inch Calculator
Have not taken EE class. Is this right?
#6 copper wire @ 5 ft
50A circuit
245V power
To charge 10 kW
@ 12A, voltage drop of 0.059v, so 0.71W loss
= 3.4 hours, so 2.41W loss on the wall.
= Add 200W loss per hour, so 682.31W loss
@ 16A, voltage drop of 0.0786v, so 1.26W loss
= 2.55 hour, so 3.21W loss
= Add 200W loss per hour, so 511.26W loss
@ 24A, voltage drop of 0.1179v, so 2.83W loss
= 1.7 hour, so 4.81W loss
= Add 200W loss per hour, so 342.83W loss
@ 32A, voltage drop of 0.1572v, so 5.03W loss
= 1.28 hour, so 6.44W loss
= Add 200W loss per hour, so 261.03W loss
Going from #6 wire to #4 wire, resistance drops from .0020 to .0012 ohm (so 40% less W loss on the wire)
If you check my post carefully, you'll see that I did that.You actually have to double those wire loss figures, because the electrons are coming in on one wire and leaving on another. Also, even if your run from load center to charger is only 5 feet, you also have to take into account losses from your high voltage transformer all the way to your charger, although much of that will be with larger gauge wiring. To know what is really happening take a look at what your car says the input voltage is at different charge rates - that should reflect all of the losses in the circuits.