That's the opposite. unless it's linear, the mass won't cancel out in the equation. It takes a greater force to stop decelerate as much a heavier vehicle and the higher the mass, the higher the friction henve the higher the force. There might be 2nd order mass corrections but the coefficient is negligible (unless you're an F1 or a massive loaded truck).I hear you, just wondering the relationship of mass and the coefficient of friction of the tire itself; is this linear? Exponential? If its linear and 1:1 proportional then the loss of coefficient of friction due to mass/load on the tire itself would negate the argument that weight doesn’t impact stopping distance.