Not really. I^2*R losses are larger at higher amperages. I noticed my line from the breaker to the 240V outlet actually felt warm when charging at 32A, which got me thinking. If I cut the charging rate to 16A, I reduce the I^2R losses by 75%. I assume there are equivalent losses in the car internals, so this could be significant. I do not see why "shortest and therefore most efficient" is valid. Is gunning a gas car all the way to the store more or less efficient than driving at a normal speed? The drive is shorter, but certainly not more efficient.