Could you write out the math for me? I am genuinely confused how you arrived at these numbers (meaning I"m trying to figure it out myself and I haven't a clue how to do it).
Replied in another thread to not derail main thread.
Model 3 pack:
Cell count: 4416
Energy content : 80 kWh
Peak charge rate: 250 kW.
At peak charge rate (if it could be maintained) the pack would fill in 80 kWh / 250 kW = 0.32 hr.
New 4680 pack with same number of cells:
Cell count: 4416
Energy Content = 5 X 80 kWh = 400 kWh. ( 5X the energy)
Peak Charge rate = 6 X 250 kW = 1500 kW (6X the power)
At 1.5 MW the 4680 pack would fill in 400 kWh / 1500 kW = 0.27 hrs.
Looking at each cell:
2170 cell energy content = 80 kWh per pack / 4416 cells per pack = 18 Wh per cell.
2170 peak charge = 250 kW per pack / 4416 cells per pack = 56.6 W per cell.
4680 cell energy content = 5 X 18 Wh / cell = 90 Wh Per cell
4680 cell peak charge = 6 X 56.6 W = 340 W per cell.
So the math is the same as the pack calculation.
bottom line English. You can charge a 4680 cell six times as fast, but you’re trying to stuff in five times as much energy, so it just gives you 1.2X leverage.