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In TRC's latest video, you can see the front seats are gone and replaced with racing buckets. The interior trim that is visible in the video has been removed as well.
In TRC's latest video, you can see the front seats are gone and replaced with racing buckets. The interior trim that is visible in the video has been removed as well.
There are no tires that will give you a better 1/4 mile time than those that come with the car. The car's acceleration is preprogrammed to match the characteristics of those tires. If you use tires that have less tack than those, your performance will be worse, but a tire with more tack will not make any difference. Anything you can do to reduce weight like lighter rims will help.
You could try drag radials from companies like M/T, Mickey Thompson, or Nitto but those will be more than terrible on the street. I don't believe anyone has tried drags on these cars. It's an expensive experiment that will likely not provide any discernable difference in 1/4 mile time except drag strip.
You could try drag radials from companies like M/T, Mickey Thompson, or Nitto but those will be more than terrible on the street. I don't believe anyone has tried drags on these cars. It's an expensive experiment that will likely not provide any discernable difference in 1/4 mile time except drag strip.
You could try drag radials from companies like M/T, Mickey Thompson, or Nitto but those will be more than terrible on the street. I don't believe anyone has tried drags on these cars. It's an expensive experiment that will likely not provide any discernable difference in 1/4 mile time except drag strip.
The ratio of 1/4 mile times cubed is equal to the ratio of the weights. t2 / t1 cubed = w2 / w1, so w2 = w1 * (t2 / t1)^3.
(10.444s / 10.7s)^3 * 5000 lbs = 0.93 * 5000 = 4650 lbs.
5000 - 4650 = 350 lbs difference for these times and weights.
Using this same formula, 10.7 to 10.6 would require about 138.9 lbs.
A 5000 lb car would have to loose 100 lbs to drop from 15.1 s to 15 s
The ratio of 1/4 mile times cubed is equal to the ratio of the weights. t2 / t1 cubed = w2 / w1, so w2 = w1 * (t2 / t1)^3.
(10.444s / 10.7s)^3 * 5000 lbs = 0.93 * 5000 = 4650 lbs.
5000 - 4650 = 350 lbs difference for these times and weights.
Using this same formula, 10.7 to 10.6 would require about 138.9 lbs.
A 5000 lb car would have to loose 100 lbs to drop from 15.1 s to 15 s