Power loss is I^2 * R and R= delta V / delta I
so you can set two different charging currents, record delta v and I. Presto! You have the resistance right to the charger and can now calculate power loss. Well I did this with the mobile connector on a circuit I extended and it came up way high.... 0.35 ohms. So I think this is high, but the distance to the box is 50ft, plus zigs and zags with #10, so high but possibly believable.
Next I install a wall connector, 35 feet of #6, terminated in the panel and hardwired on the wall connector. Repeat calculation... 0.2 ohms??? 10x what it should be. I am convinced the voltage measurement is poor for sure on the wall connector, possibly on the mobile. Comments??
so you can set two different charging currents, record delta v and I. Presto! You have the resistance right to the charger and can now calculate power loss. Well I did this with the mobile connector on a circuit I extended and it came up way high.... 0.35 ohms. So I think this is high, but the distance to the box is 50ft, plus zigs and zags with #10, so high but possibly believable.
Next I install a wall connector, 35 feet of #6, terminated in the panel and hardwired on the wall connector. Repeat calculation... 0.2 ohms??? 10x what it should be. I am convinced the voltage measurement is poor for sure on the wall connector, possibly on the mobile. Comments??