Coming from a position of discussion, not argument.
One question would be :- How well and electric system could compensate and prevent a sudden unexpected failure?
Perhaps 16V battery or an oversized variant could provide an alternative power source.
Perhaps each wheel can have a capacitor to drive the electronic function, which can be charged from with either battery.
IMO all options are worth exploring, because ditching hydraulics does seem like it would make cars cheaper and easier to build.
Airbag modules, black box data recorders, and (I think) some electronically latched doors do this now. However, on loss of power to one brake, when is the correct action to brake that wheel?
Other than the centralized ABS module, hydraulic brakes are hella simple to make and produce. The outboard hardware is also quite durable.
Installation (other than bleeding) is fairly equivalent to harness routing. Replacement later can be a pain though.
Even if the "Diamond Steering" video is likely to be well of target on some points, I do agree with the general premise.
Simply Tesla would be looking at all options to reduce cost and complexity when building the Cybertruck.
"This is the way we have always done it", will not be taken seriously
"This is the cheapest and best solution" will, that doesn't need to be a solution currently in use by most of the industry.
The aim isn't to achieve "party tricks", merely to demonstrate "party tricks" when good engineering means they are an added advantage of decisions already made.
Even as a party trick the tank turn is of limited value, any driver who genuinely needs to use a tank turn to get out of a situation can't drive a car in reverse.
Best part is no part.
Cybertruck with quad motors already has per wheel braking ability via regen.
In duplicating modules, there is also the reliability probability problem. The odds of all modules working decreases as the number of modules increases, even as the odds of at least one module still working increase.
If chance of failure is f, and number of modules is n, then odds of a failure are (1-(1-f)^n).
Pure for illustration: 20% chance of failure per module
Chance of at least one module failure:
n=1: 20%
n=2: 36%
n=4: 59%
This is pary of why new large planes have two engines instead of 4.