There will never be 100% efficient chemical battery. And the core (center part) of the cell will get too hot, even if you have unlimited amount of cooling around the cell available.
Except that the rate of dissipation from the core to the outside is related to the temperature differential between the inside and the outside. So there's a world of difference between chilling your coolant to ambient vs. to just above freezing. So, unless you're planning to install a 10 ton industrial chiller in the vehicle.....
And this is, by the way, an entire separate, additional issue to the issue of getting the heat out of the pack coolant.
Imagine Tesla's 100kWh battery charging at speed up to 250kW. Something similar.
And giving off over double the heat.
Well, without going above 400V, charge rates will never get down to those approaching gasoline fill times.
Simply false, no matter how much you boldface it. But if you want boldface in your response: to increase power, you can increase either the voltage or the current. Since you have to provide coolant anyway for the battery pack to dissipate the vastly higher cooling needs, then you're already cooling the cable, and thus can provide vastly higher currents on the same amount of copper.
I leave you with hometask: 50:50 ethylene glycol mix and normal maximum flow by coolant pump without turbulent flow. Try to extract any number of kW of heat you desire. Let's say 10kW extraction rate from vehicle. Choose your hose dimensions.
Yes. It is called science. No science, no real thing. Just speculation.
Funny that you're acting as if you're the one running numbers when I'm the only person in this entire thread who's actually conducted calculations. And now that you need numbers run, rather than conducting them yourself, you insist that I do them - with a mocking tone at that. Well, fine, because it's a simple request. The specific heat of a 50% ethylene glycol mix is 1814 J/kg-°C at around 0°. Let's say that we want to limit the heat rise in the pack to 10°C, so the fluid can handle 18140J/kg, or 18,14J/g. 10kW is nothing in terms of pack heating, but let's go with your figures. A kW is a kJ/s, so 551g/s. The specific gravity at 0°C is around 1.1g/cm³, meaning a flow rate of around 501cm³ per second, or 0,000501m³/s. What's our limiting pressure drop? Let's plug in the numbers for 1cm x 4m tubing. For water that would be a pressure drop of 1609 mbar The pressure drop for a 50-50 glycol water mix at those temperatures is reported to be 45% that of water, or 724mbar. What's the problem? We're talking 345 grams of glycol in the entire 4m length. Want a lower pressure drop? Increase the diameter from 1cm; it's still a small mass. 2cm and the pressure drop decreases to 26mbar.
What problem exactly where you expecting? It's pretty silly that you expected a problem to begin with, given that the car itself already has to move these volumes of fluid through its radiator. The concept that the car could handle it but a charger couldn't makes no sense at all.
The fact that you'd bring up air cooled copper is precisely the problem. Air cooling is vastly slower than liquid cooling. Today you have an air-cooled cable, and a vehicle getting rid of its heat with a radiator, to the air. Rather than a liquid-cooled cable and getting rid of its heat via transfer to liquid. If you rely on air cooling your cable, you have to use a heavy cable per unit power. If you rely on a radiator to get rid of charging heat, you're limited to your coolant being ambient temperature and having a high ratio of radiator mass to heat loss rate.
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