adregia
Member
The EPA requires the manufacturer to submit three target coefficients (available here) that play into a formula that looks something like follows:While I don't doubt that the Model Y is more efficient than the ID.4, unfortunately it's difficult to compare even EPA ratings since manufacturers are able to adjust the scaling factors in the results and test differently.
Really need some real world tests to get a better idea. I really wish that a simple 65-70 mph steady state test was part of the test and easily available.
A + Bv + Cv^2 = road force in ft lbf.
If you can do some math, you can multiply by any given velocity (i.e., 70 mph), convert ft lbf into kWh, and divide the usable size of the battery by that number to determine how many feet the car can travel on a single charge in extremely ideal conditions.
I.e., for a LR Model 3 at 75 mph, the coefficients are 38.61, -0.0811, and 0.0161, which comes out to 123.08 ft lbf at 75 mph. Convert it into kWh (about 0.245 per mile), divide the size of the battery by this number (~79 kWh), and you get ~320 miles in extremely ideal conditions, not accounting for road texture, wind, grade of the road, AC, etc.
This is just one of many factors that play into the EPA range estimates, but it was worth mentioning.