Dusting off the Grammar School Physics memories here but if
Watts = Volts x Amps
and I have the HPWC on a 240v circuit set to 30A, which for the 80% rule is really a 24A pull, then I'm drawing
240 x 24 ==> 5760 Watts or 5.76 kW
and if I do that for an hour I will have used 5.76 kWh - might as well call that 6 kWh
and looking at my plan, I'm paying somewhere between 8.6 and 9.1 cents per kWh [1] (and 100% renewable ) so call that 9c per kWh
Therefore it costs me 54 cents an hour to charge my vehicle at home
Now all I need to figure out is how far I go on that amount of charge
[1] I change to a new provider every time the plan expires as the "new customer" rates are always better than the ones for existing customers - sort of a reverse loyalty program
Watts = Volts x Amps
and I have the HPWC on a 240v circuit set to 30A, which for the 80% rule is really a 24A pull, then I'm drawing
240 x 24 ==> 5760 Watts or 5.76 kW
and if I do that for an hour I will have used 5.76 kWh - might as well call that 6 kWh
and looking at my plan, I'm paying somewhere between 8.6 and 9.1 cents per kWh [1] (and 100% renewable ) so call that 9c per kWh
Therefore it costs me 54 cents an hour to charge my vehicle at home
Now all I need to figure out is how far I go on that amount of charge
[1] I change to a new provider every time the plan expires as the "new customer" rates are always better than the ones for existing customers - sort of a reverse loyalty program