Quickly used some calculators. I might have screwed this up.
Assuming: 10kg spinning @ radius of 8 inches (this is obviously approximate and probably overestimates the energy of the additional spinning weight?)
At 60mph, wheels are spinning at: 88ft/sec, circumference is 6.89ft, so 12.77rev/sec
Angular velocity: 80.2rad/sec
Moment of inertia: m*r^2 = 10kg*0.2m^2 = 0.4kg*m^2
Rotational KE: 0.5*I*omega^2 = 0.5 * 0.4kg/m^2 * 80.2^2/sec = 1286kg*m^2/s^2 = 1286joules
KE of vehicle at 60mph is 1/2*m*v^2 = 1/2*4100lbs*60mph^2 = 669kJ
So an additional 0.2% improvement beyond the weight savings if you drop that weight?
Please correct obvious errors here. Maybe I'm off by a factor of 10 somewhere? I don't have a feel for what is reasonable, though it seems like the answer would be a small (but significant if you're racing!) effect. This answer due to rotational KE only would drop ~10ms off the 0-60. The weight would be an additional 20ms, so total would be 30ms better 0-60. That's not nothing!
Some results from people here suggest it could be more like 100ms though (could be vehicle variation or driver weight though). But maybe calculations are wrong.