AlanSubie4Life
Efficiency Obsessed Member
You can also increase power by lowering the battery's internal resistance. Voltage sags as the current draw goes up due to the internal resistance of the battery. No-load terminal voltage might be 400V, but place a 1200A draw on the battery and terminal voltage might sink to 300V, maybe lower with lower states of charge.
Lower the battery's internal resistance through different cell construction or different cell materials, and the voltage will sag less. The same 1200A draw might only sink voltage to 325V, which means an extra 30 kW of power output.
Yes. We don't know how the new denser battery behaves (maybe @MasterC17 could compare & log the CAN bus reported voltage under WOT to 60+mph between the two vehicles!). But there are reasons to believe (namely, because this is how other Panasonic lithium cells work) a denser, higher capacity battery would tend to increase internal resistance and reduce maximum output current for a given sag. They were probably careful in this case to make appropriate design optimizations to ensure that it didn't change much for this new cell, though (meaning, the cell is just "better," moving the capacity/performance envelope outwards).