Well as someone with a physics degree I am just going to say centripetal; not centrifugal. But yes; more mass = more resistant to change direction and more resistant to slow down: more braking force needed to reduce speed.
Inertia wants to keep doing what it is doing. (Thank you Isaac Newton)
But the most important thing is not power but getting power to the ground.
I am not disagreeing with anything you are saying, but I will explain my point with a formula one car: It has twice the force towards the tarmac; that is twice the weight at speeds above 100mph due to its ground effects (aero). yes, that means it can drive upside down in a tunnel at high speeds. It actually accelerates quicker from 100-200 than it does from 0-100 because of this added "weight" . Weight (force of gravity) is traction. (as well as coefficient of friction between hot rubber and asphalt)
so if there is a huge amount of downforce which essentially turns a 740 kg racecar into essentially a 1600 kg car at higher speeds, is that not the same as having to turn a 1600 kg car in the corners and slow it down?
The reason they want a light weight on a racecar is really for acceleration ( estimate 7 lbs = 1 hp); to which the electric vehicle has no issue with.
Thanks for correction of centripetal vs centrifugal. I always get the two confused.
But the reason F1 and race cars in general go lighter weight is for cornering and braking, but acceleration. Best way to think of this is the force components that tire need to counter in order to maintain traction.
In a corner, the tire will see a lateral component from centripetal force, which has the car mass component in there. It would also see a significant longitudinal force when a car is accelerating or decelerating. To counter this, the tire needs the friction force, which is normal force x coefficient of friction. The normal force component is primary made of weight of the car and the downforce. As the mass of the car goes up, that normal force increase, but it also increase the lateral loads on the tire because the centripetal component goes up. As the cornering velocity goes up, the v^2/r component goes up beyond gravity. To make up for this, the tire coefficient of friction needs to go up. As you can see, it gets to a point where tire itself won't work. Now, instead of doing that, you at downforce, which increase the normal force used to generate tire friction force, but without the penalty of increasing lateral loads. And downforce goes up by v^2 as well, so it does well in countering against centripetal force from cornering.