How many Teslas do you think are on the latest ship? Here's one calculation.
The draft of the ship increased by 1.3 meters
1.3 meters = 4.27 feet
Length and beam of the ship is 199.94 x 32.26 meters
199.94 x 32.26=6449 sq. meters
6449 sq. meters= 69,416 sq. ft.
Increase in displacement
69,416 sq ft x4.27 ft = 296,406 cu ft
water weights 62.4 lb/cu ft
296,406 cu ft x 62.4 lb/cu ft = 18,495,734 lb
I we assume that at area of the ship at the water line is only 90% of the overall dimension to allow for some slope at the bow and stern then the increased displacement becomes (SWAG):
18,495,734 lb x 90%= 16,646,160 lb increased displacement
If the average weight of M3 is 3900 lb
16,646,160 lb/3900 lb per vehicle = 4268 vehicles
Possible errors/poor assumptions:
- Area of ship at waterline vs overall dimensions at 90%
- Weight of vehicles and mix of vehicles
- Other items loaded than Teslas
- Rounding errors. I should have used a piece of paper.
- I used the density of fresh water instead of salt water but the difference should not be significant considering the other assumptions made.
Here's a starting point for the discussion. I welcome any gentle comments/corrections. It would be great if this were anywhere close to being correct.