AlanSubie4Life
Efficiency Obsessed Member
Curious what your source is for that because I actually every physics textbook that I've ever consulted about this says that your power consumption is proportional to the square of your velocity cuz most of it is actually drag. And that's proportional to Velocity squared not cubed. Has data against the cubed supposition, I can measure my Watt hours per mile at 40 miles an hour and depending on temperature at somewhere between 180 and 190 Watt hours per mile and it is exactly doubled at 80 miles per hour. This is not possible if your formula is correct.
Force required to overcome drag goes up with square of velocity. So force, and thus work (energy) for a fixed distance go up with the square of velocity. However, since you get there faster (time inversely proportional to velocity), and therefore the work is done faster, and power is the rate of producing work, the resulting required power goes up as the cube of velocity. But energy required from point A to B would scale with the square.
So your Wh/mi numbers are correct and scale with the square, but required power goes up with the cube of velocity.